Deeply concatenable subgroups might never be free
نویسندگان
چکیده
منابع مشابه
Wondering What Might Be
This paper explores the possibility of supplementing the suppositional view of indicative conditionals with a corresponding view of epistemic modals. The most striking feature of the suppositional view consists in its claim that indicative conditionals are to be evaluated by conditional probabilities. On the basis of a natural link between indicative conditionals and epistemic modals, a corresp...
متن کاملCity logistics in Spain: Why it might never work
Urban freight deliveries depend strongly on local regulations and policies to guarantee a tidy and efficient flow of goods towards commercial premises. However, the urban freight delivery system in Spain, which is even more complicated due to the urban morphology and driving behavior, also suffers from a combination of negative factors, including uneven regulations, lack of enforcement and obso...
متن کاملWhy Computers Will Never Be People
The notion that computers and robots either have a measure of intelligence, or at least will have at some stage, has firmly taken root in Western culture. It has inspired a slew of science fiction novels and films, and one of these, ‘The Matrix’, has attained the status of a modern classic. Moreover, it has powerful advocates in the scientific and philosophical fraternities, the most prominent ...
متن کاملLife Will Never Be the Same
It seems appropriate that the Cold Spring Harbor Genome Sequencing and Biology Meeting, which witnessed the creation of the Human Genome Organization (HUGO) in 1988, should this year present three major advances in genomic science: the completion of the ®nished sequence of Drosophila melanogaster; the announcement that 85% of the genome of Homo sapiens is now in draft sequence; and the complete...
متن کاملB(ℓ p ) can never be amenable
We show that, if E is a Banach space with a basis satisfying a certain condition, then the Banach algebra l∞(K(l2 ⊕ E)) is not amenable; in particular, this is true for E = l with p ∈ (1,∞). As a consequence, l∞(K(E)) is not amenable for any infinite-dimensional Lp-space. This, in turn, entails the non-amenability of B(lp(E)) for any Lp-space E, so that, in particular, B(lp) and B(Lp[0, 1]) are...
متن کاملذخیره در منابع من
با ذخیره ی این منبع در منابع من، دسترسی به آن را برای استفاده های بعدی آسان تر کنید
ژورنال
عنوان ژورنال: Journal of the Mathematical Society of Japan
سال: 2019
ISSN: 0025-5645
DOI: 10.2969/jmsj/80498049